Expanded Form and Simplification of Algebraic Expressions

Oct 13, 2025 by sorusgentrification.com 9 views

Expanded Form and Simplification of Algebraic Expressions

8. a) Expanded Form of (a-b)^2

The expanded form of a quadratic expression in the form of (a-b)^2 can be obtained by using the formula (a-b)^2 = a^2 - 2ab + b^2. This formula is derived from the binomial expansion of (a-b)^2.

To expand (a-b)^2, we can start by multiplying (a-b) by itself:

(a-b)(a-b) = a^2 - ab - ab + b^2

Now, we can combine like terms:

a^2 - 2ab + b^2

Therefore, the expanded form of (a-b)^2 is a^2 - 2ab + b^2.

8. b) Simplification of (3x)^2 × (2x)^3 × (5x)^3

To simplify the expression (3x)^2 × (2x)^3 × (5x)^3, we can start by expanding each term:

(3x)^2 = 9x^2 (2x)^3 = 8x^3 (5x)^3 = 125x^3

Now, we can multiply these terms together:

9x^2 × 8x^3 × 125x^3

To simplify this expression, we can combine like terms:

9 × 8 × 125 = 11250 x^2 × x^3 × x^3 = x^8

Therefore, the simplified form of (3x)^2 × (2x)^3 × (5x)^3 is 11250x^8.

9. If the Sum of Four Times One Number and Another Number is 7

9. a) Represented Equations

Let's say the two numbers are x and y. We can represent the given information as an equation:

4x + y = 7

This equation states that the sum of four times one number (x) and another number (y) is 7.

9. b) If One Number is 15, Find the Other Number

If one number is 15, we can substitute this value into the equation:

4x + y = 7 4(15) + y = 7

Now, we can simplify this equation:

60 + y = 7

To find the value of y, we can subtract 60 from both sides of the equation:

y = 7 - 60 y = -53

Therefore, if one number is 15, the other number is -53.

Solving Linear Equations

What are Linear Equations?

A linear equation is an equation in which the highest power of the variable(s) is 1. In other words, a linear equation is an equation that can be written in the form ax + b = c, where a, b, and c are constants, and x is the variable.

Examples of Linear Equations

Here are some examples of linear equations:

2x + 3 = 5 x - 2 = 3 4x = 12

How to Solve Linear Equations

To solve a linear equation, we can use the following steps:

Add or subtract the same value to both sides of the equation to isolate the variable.
Multiply or divide both sides of the equation by the same value to isolate the variable.

Example 1: Solving the Equation 2x + 3 = 5

To solve the equation 2x + 3 = 5, we can start by subtracting 3 from both sides of the equation:

2x + 3 - 3 = 5 - 3 2x = 2

Now, we can divide both sides of the equation by 2 to solve for x:

x = 2/2 x = 1

Therefore, the solution to the equation 2x + 3 = 5 is x = 1.

Example 2: Solving the Equation x - 2 = 3

To solve the equation x - 2 = 3, we can start by adding 2 to both sides of the equation:

x - 2 + 2 = 3 + 2 x = 5

Therefore, the solution to the equation x - 2 = 3 is x = 5.

Example 3: Solving the Equation 4x = 12

To solve the equation 4x = 12, we can start by dividing both sides of the equation by 4:

4x/4 = 12/4 x = 3

Therefore, the solution to the equation 4x = 12 is x = 3.

Conclusion

In this article, we have discussed the expanded form and simplification of algebraic expressions, as well as solving linear equations. We have also provided examples of linear equations and shown how to solve them using the steps outlined above. By following these steps, we can solve linear equations and find the value of the variable.
Q&A: Algebraic Expressions and Linear Equations

Q: What is the expanded form of (a+b)^2?

A: The expanded form of (a+b)^2 is a^2 + 2ab + b^2.

Q: How do you simplify the expression (3x)^2 × (2x)^3 × (5x)^3?

A: To simplify the expression (3x)^2 × (2x)^3 × (5x)^3, we can start by expanding each term:

(3x)^2 = 9x^2 (2x)^3 = 8x^3 (5x)^3 = 125x^3

Then, we can multiply these terms together:

9x^2 × 8x^3 × 125x^3 = 11250x^8

Q: What is the equation for the sum of four times one number and another number?

A: The equation for the sum of four times one number and another number is 4x + y = 7.

Q: If one number is 15, find the other number.

A: If one number is 15, we can substitute this value into the equation:

4x + y = 7 4(15) + y = 7

Now, we can simplify this equation:

60 + y = 7

To find the value of y, we can subtract 60 from both sides of the equation:

y = 7 - 60 y = -53

Therefore, if one number is 15, the other number is -53.

Q: What is a linear equation?

A: A linear equation is an equation in which the highest power of the variable(s) is 1. In other words, a linear equation is an equation that can be written in the form ax + b = c, where a, b, and c are constants, and x is the variable.

Q: How do you solve a linear equation?

A: To solve a linear equation, we can use the following steps:

Add or subtract the same value to both sides of the equation to isolate the variable.
Multiply or divide both sides of the equation by the same value to isolate the variable.

Q: Can you provide an example of solving a linear equation?

A: Let's say we want to solve the equation 2x + 3 = 5. We can start by subtracting 3 from both sides of the equation:

2x + 3 - 3 = 5 - 3 2x = 2

Now, we can divide both sides of the equation by 2 to solve for x:

x = 2/2 x = 1

Therefore, the solution to the equation 2x + 3 = 5 is x = 1.

Q: What is the difference between a linear equation and a quadratic equation?

A: A linear equation is an equation in which the highest power of the variable(s) is 1, while a quadratic equation is an equation in which the highest power of the variable(s) is 2. In other words, a linear equation is an equation that can be written in the form ax + b = c, while a quadratic equation is an equation that can be written in the form ax^2 + bx + c = 0.

Q: Can you provide an example of a quadratic equation?

A: Let's say we want to solve the equation x^2 + 4x + 4 = 0. We can start by factoring the left-hand side of the equation:

(x + 2)(x + 2) = 0

Now, we can set each factor equal to 0 and solve for x:

x + 2 = 0 x = -2

Therefore, the solution to the equation x^2 + 4x + 4 = 0 is x = -2.

Conclusion

In this article, we have provided answers to common questions about algebraic expressions and linear equations. We have also provided examples of solving linear equations and quadratic equations. By following the steps outlined above, we can solve linear equations and find the value of the variable.