Proof of the Difference Quotient

Oct 13, 2025 by sorusgentrification.com 0 views

Introduction

In calculus, the difference quotient is a fundamental concept used to find the derivative of a function. It is defined as the limit of the difference quotient as the change in the input variable approaches zero. In this article, we will find the difference quotient of the quadratic function ${$ f(x) = 3x^2 + 8$}$.

Step 1: Calculate ${$ f(x+h)$}$

To find the difference quotient, we first need to calculate ${$ f(x+h)$}$. This involves substituting ${$ x+h$}$ into the function ${$ f(x) = 3x^2 + 8$}$.

${$ f(x+h) = 3(x+h)^2 + 8$}$

Using the binomial expansion, we can expand ${$ (x+h)^2$}$ as follows:

${$ (x+h)^2 = x^2 + 2xh + h^2$}$

Substituting this into the expression for ${$ f(x+h)$}$, we get:

${$ f(x+h) = 3(x^2 + 2xh + h^2) + 8$}$

Step 2: Simplify the Expression

Now that we have calculated ${$ f(x+h)$}$, we can simplify the expression by distributing the 3 to the terms inside the parentheses:

${$ f(x+h) = 3x^2 + 6xh + 3h^2 + 8$}$

Step 3: Find the Difference Quotient

The difference quotient is defined as the limit of the difference quotient as the change in the input variable approaches zero. Mathematically, this can be represented as:

${$ \left(\frac{f(x+h)-f(x)}{h}\right)$}$

To find the difference quotient, we need to substitute the expressions for ${$ f(x+h)$}$ and ${$ f(x)$}$ into this formula.

${$ \left(\frac{(3x^2 + 6xh + 3h^2 + 8) - (3x^2 + 8)}{h}\right)$}$

Simplifying the expression inside the parentheses, we get:

${$ \left(\frac{6xh + 3h^2}{h}\right)$}$

Step 4: Simplify the Expression Further

Now that we have simplified the expression inside the parentheses, we can simplify the expression further by canceling out the common factor of ${$ h$}$:

${$ \left(\frac{6xh}{h} + \frac{3h^2}{h}\right)$}$

${ $6x + 3h\$}$

However, we are interested in finding the limit as ${$ h$}$ approaches zero. Therefore, we can ignore the term ${ $3h\$}$ and focus on the term ${ $6x\$}$ .

Conclusion

In this article, we found the difference quotient of the quadratic function ${$ f(x) = 3x^2 + 8$}$. We started by calculating ${$ f(x+h)$}$ and then simplified the expression to find the difference quotient. Finally, we simplified the expression further to find the limit as ${$ h$}$ approaches zero.

The Final Answer

The final answer is ${ $6x\$}$ .

Discussion

The difference quotient is a fundamental concept in calculus that is used to find the derivative of a function. In this article, we found the difference quotient of the quadratic function ${$ f(x) = 3x^2 + 8$}$. The difference quotient is defined as the limit of the difference quotient as the change in the input variable approaches zero.

Example Use Cases

The difference quotient has many practical applications in fields such as physics, engineering, and economics. For example, it can be used to model the motion of an object under the influence of gravity, or to analyze the behavior of a complex system.

Limitations

While the difference quotient is a powerful tool for finding derivatives, it has some limitations. For example, it can be difficult to use when the function is not differentiable at a particular point. In such cases, other methods such as the limit definition of a derivative may be more suitable.

Future Work

In future work, we plan to explore other applications of the difference quotient in fields such as physics and engineering. We also plan to investigate the use of the difference quotient in more complex systems, such as those involving multiple variables.

References

[1] Calculus, 3rd edition, Michael Spivak
[2] Calculus, 2nd edition, James Stewart
[3] The Calculus Page, Paul Dawkins

Appendix

A. Proof of the Difference Quotient

The difference quotient can be proved using the following steps:

Start with the definition of the difference quotient:

${$ \left(\frac{f(x+h)-f(x)}{h}\right)$}$

Substitute the expressions for ${$ f(x+h)$}$ and ${$ f(x)$}$ into this formula:

${$ \left(\frac{(3x^2 + 6xh + 3h^2 + 8) - (3x^2 + 8)}{h}\right)$}$

Simplify the expression inside the parentheses:

${$ \left(\frac{6xh + 3h^2}{h}\right)$}$

Simplify the expression further by canceling out the common factor of ${$ h$}$:

${$ \left(\frac{6xh}{h} + \frac{3h^2}{h}\right)$}$

Evaluate the limit as ${$ h$}$ approaches zero:

${ $6x + 3h\$}$

Ignore the term ${ $3h\$}$ and focus on the term ${ $6x\$}$ :

${ $6x\$}$

B. Derivative of a Quadratic Function

The derivative of a quadratic function can be found using the difference quotient. For example, if we have the quadratic function ${$ f(x) = 3x^2 + 8$}$, we can find its derivative using the difference quotient:

${$ \left(\frac{f(x+h)-f(x)}{h}\right)$}$

${$ \left(\frac{(3x^2 + 6xh + 3h^2 + 8) - (3x^2 + 8)}{h}\right)$}$

${$ \left(\frac{6xh + 3h^2}{h}\right)$}$

${ $6x + 3h\$}$

${ $6x\$}$

Introduction

In our previous article, we explored the concept of the difference quotient and how it can be used to find the derivative of a function. In this article, we will answer some common questions related to the difference quotient and derivatives.

Q: What is the difference quotient?

A: The difference quotient is a mathematical concept used to find the derivative of a function. It is defined as the limit of the difference quotient as the change in the input variable approaches zero.

Q: How do I calculate the difference quotient?

A: To calculate the difference quotient, you need to follow these steps:

Calculate ${$ f(x+h)$}$ by substituting ${$ x+h$}$ into the function ${$ f(x)$].
Simplify the expression for [ $f(x+h)\$}$ .
Find the difference quotient by substituting the expressions for ${$ f(x+h)$}$ and ${$ f(x)$}$ into the formula ${$ \left(\frac{f(x+h)-f(x)}{h}\right)$}$.
Simplify the expression further by canceling out the common factor of ${$ h$}$.
Evaluate the limit as ${$ h$}$ approaches zero.

Q: What is the derivative of a function?

A: The derivative of a function is a measure of how the function changes as the input variable changes. It is defined as the limit of the difference quotient as the change in the input variable approaches zero.

Q: How do I find the derivative of a function using the difference quotient?

A: To find the derivative of a function using the difference quotient, you need to follow these steps:

Calculate ${$ f(x+h)$}$ by substituting ${$ x+h$}$ into the function ${$ f(x)$].
Simplify the expression for [ $f(x+h)\$}$ .
Find the difference quotient by substituting the expressions for ${$ f(x+h)$}$ and ${$ f(x)$}$ into the formula ${$ \left(\frac{f(x+h)-f(x)}{h}\right)$}$.
Simplify the expression further by canceling out the common factor of ${$ h$}$.
Evaluate the limit as ${$ h$}$ approaches zero.

Q: What are some common applications of the difference quotient?

A: The difference quotient has many practical applications in fields such as physics, engineering, and economics. Some common applications include:

Modeling the motion of an object under the influence of gravity
Analyzing the behavior of a complex system
Finding the derivative of a function

Q: What are some common mistakes to avoid when using the difference quotient?

A: Some common mistakes to avoid when using the difference quotient include:

Failing to simplify the expression for ${$ f(x+h)$}$
Failing to cancel out the common factor of ${$ h$}$
Evaluating the limit as ${$ h$}$ approaches zero incorrectly

Q: How do I know if the difference quotient is defined for a particular function?

A: The difference quotient is defined for a particular function if the function is differentiable at the point in question. To check if the difference quotient is defined, you need to check if the function is continuous and if the limit of the difference quotient as ${$ h$}$ approaches zero exists.

Q: What are some common functions that are not differentiable?

A: Some common functions that are not differentiable include:

Absolute value functions
Step functions
Functions with sharp corners or cusps

Conclusion

In this article, we answered some common questions related to the difference quotient and derivatives. We hope that this article has been helpful in clarifying some of the concepts related to the difference quotient and derivatives. If you have any further questions, please don't hesitate to ask.

References

[1] Calculus, 3rd edition, Michael Spivak
[2] Calculus, 2nd edition, James Stewart
[3] The Calculus Page, Paul Dawkins

Appendix

A. Proof of the Difference Quotient

The difference quotient can be proved using the following steps:

Start with the definition of the difference quotient:

${$ \left(\frac{f(x+h)-f(x)}{h}\right)$}$

Substitute the expressions for ${$ f(x+h)$}$ and ${$ f(x)$}$ into this formula:

${$ \left(\frac{(3x^2 + 6xh + 3h^2 + 8) - (3x^2 + 8)}{h}\right)$}$

Simplify the expression inside the parentheses:

${$ \left(\frac{6xh + 3h^2}{h}\right)$}$

Simplify the expression further by canceling out the common factor of ${$ h$}$:

${$ \left(\frac{6xh}{h} + \frac{3h^2}{h}\right)$}$

Evaluate the limit as ${$ h$}$ approaches zero:

${ $6x + 3h\$}$

Ignore the term ${ $3h\$}$ and focus on the term ${ $6x\$}$ :

${ $6x\$}$

B. Derivative of a Quadratic Function

${$ \left(\frac{f(x+h)-f(x)}{h}\right)$}$

${$ \left(\frac{(3x^2 + 6xh + 3h^2 + 8) - (3x^2 + 8)}{h}\right)$}$

${$ \left(\frac{6xh + 3h^2}{h}\right)$}$

${ $6x + 3h\$}$

${ $6x\$}$

Therefore, the derivative of the quadratic function ${$ f(x) = 3x^2 + 8$}$ is ${ $6x\$}$ .