Quadratic Equations and Their Graphs

Oct 13, 2025 by sorusgentrification.com 75 views

**Which Equation Represents a Graph with a Vertex at (-3, 2)?**

Understanding the Problem

In this article, we will explore the concept of quadratic equations and their graphs. We will focus on identifying the equation that represents a graph with a vertex at (-3, 2). This problem requires a deep understanding of quadratic equations, their standard form, and the process of completing the square.

Quadratic Equations and Their Graphs

A quadratic equation is a polynomial equation of degree two, which means the highest power of the variable is two. The general form of a quadratic equation is:

ax^2 + bx + c = 0

where a, b, and c are constants, and x is the variable. The graph of a quadratic equation is a parabola, which is a U-shaped curve.

Vertex Form of a Quadratic Equation

The vertex form of a quadratic equation is:

y = a(x - h)^2 + k

where (h, k) is the vertex of the parabola. In this form, the vertex is the point where the parabola changes direction.

Completing the Square

To convert a quadratic equation from standard form to vertex form, we need to complete the square. This involves rewriting the equation in a way that allows us to easily identify the vertex.

Step 1: Factor out the Coefficient of x^2

The first step in completing the square is to factor out the coefficient of x^2. This will make it easier to complete the square.

Step 2: Add and Subtract the Square of Half the Coefficient of x

Next, we add and subtract the square of half the coefficient of x. This will create a perfect square trinomial.

Step 3: Simplify the Equation

Finally, we simplify the equation by combining like terms.

Example: Completing the Square

Let's consider the quadratic equation:

y = 4x^2 + 24x + 38

To complete the square, we first factor out the coefficient of x^2:

y = 4(x^2 + 6x) + 38

Next, we add and subtract the square of half the coefficient of x:

y = 4(x^2 + 6x + 9 - 9) + 38

Now, we simplify the equation:

y = 4(x + 3)^2 - 36 + 38

y = 4(x + 3)^2 + 2

Identifying the Vertex

Now that we have completed the square, we can easily identify the vertex of the parabola. In this case, the vertex is (-3, 2).

Which Equation Represents a Graph with a Vertex at (-3, 2)?

Now that we have a deep understanding of quadratic equations and their graphs, we can identify the equation that represents a graph with a vertex at (-3, 2).

A. y = 4x^2 + 24x + 38

This equation does not represent a graph with a vertex at (-3, 2).

B. y = 4x^2 - 24x + 38

This equation does not represent a graph with a vertex at (-3, 2).

C. y = 4x^2 + 12x + 2

This equation represents a graph with a vertex at (-3, 2).

D. y = 4x^2 + 16x + 13

This equation does not represent a graph with a vertex at (-3, 2).

Conclusion

In this article, we explored the concept of quadratic equations and their graphs. We focused on identifying the equation that represents a graph with a vertex at (-3, 2). We completed the square to convert the equation from standard form to vertex form and identified the vertex of the parabola. We found that the equation y = 4x^2 + 12x + 2 represents a graph with a vertex at (-3, 2).

Frequently Asked Questions

Q: What is the vertex form of a quadratic equation?

A: The vertex form of a quadratic equation is y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.

Q: How do I complete the square to convert a quadratic equation from standard form to vertex form?

A: To complete the square, you need to factor out the coefficient of x^2, add and subtract the square of half the coefficient of x, and simplify the equation.

Q: What is the significance of the vertex of a parabola?

A: The vertex of a parabola is the point where the parabola changes direction.

Q: How do I identify the vertex of a parabola?

A: To identify the vertex of a parabola, you need to complete the square and rewrite the equation in vertex form.

Q: What is the equation that represents a graph with a vertex at (-3, 2)?

A: The equation that represents a graph with a vertex at (-3, 2) is y = 4x^2 + 12x + 2.